8q^2-5q=7q^2-9q+32

Simple and best practice solution for 8q^2-5q=7q^2-9q+32 equation. Check how easy it is, and learn it for the future. Our solution is simple, and easy to understand, so don`t hesitate to use it as a solution of your homework.

If it's not what You are looking for type in the equation solver your own equation and let us solve it.

Solution for 8q^2-5q=7q^2-9q+32 equation: 


Simplifying
8q2 + -5q = 7q2 + -9q + 32

Reorder the terms:
-5q + 8q2 = 7q2 + -9q + 32

Reorder the terms:
-5q + 8q2 = 32 + -9q + 7q2

Solving
-5q + 8q2 = 32 + -9q + 7q2

Solving for variable 'q'.

Reorder the terms:
-32 + -5q + 9q + 8q2 + -7q2 = 32 + -9q + 7q2 + -32 + 9q + -7q2

Combine like terms: -5q + 9q = 4q
-32 + 4q + 8q2 + -7q2 = 32 + -9q + 7q2 + -32 + 9q + -7q2

Combine like terms: 8q2 + -7q2 = 1q2
-32 + 4q + 1q2 = 32 + -9q + 7q2 + -32 + 9q + -7q2

Reorder the terms:
-32 + 4q + 1q2 = 32 + -32 + -9q + 9q + 7q2 + -7q2

Combine like terms: 32 + -32 = 0
-32 + 4q + 1q2 = 0 + -9q + 9q + 7q2 + -7q2
-32 + 4q + 1q2 = -9q + 9q + 7q2 + -7q2

Combine like terms: -9q + 9q = 0
-32 + 4q + 1q2 = 0 + 7q2 + -7q2
-32 + 4q + 1q2 = 7q2 + -7q2

Combine like terms: 7q2 + -7q2 = 0
-32 + 4q + 1q2 = 0

Factor a trinomial.
(-8 + -1q)(4 + -1q) = 0


Subproblem 1
Set the factor '(-8 + -1q)' equal to zero and attempt to solve:

Simplifying
-8 + -1q = 0

Solving
-8 + -1q = 0

Move all terms containing q to the left, all other terms to the right.

Add '8' to each side of the equation.
-8 + 8 + -1q = 0 + 8

Combine like terms: -8 + 8 = 0
0 + -1q = 0 + 8
-1q = 0 + 8

Combine like terms: 0 + 8 = 8
-1q = 8

Divide each side by '-1'.
q = -8

Simplifying
q = -8

Subproblem 2
Set the factor '(4 + -1q)' equal to zero and attempt to solve:

Simplifying
4 + -1q = 0

Solving
4 + -1q = 0

Move all terms containing q to the left, all other terms to the right.

Add '-4' to each side of the equation.
4 + -4 + -1q = 0 + -4

Combine like terms: 4 + -4 = 0
0 + -1q = 0 + -4
-1q = 0 + -4

Combine like terms: 0 + -4 = -4
-1q = -4

Divide each side by '-1'.
q = 4

Simplifying
q = 4
Solution
q = {-8, 4}

See similar equations:

| 113-3n=8 | | (2x+1)=-3(x+3) | | y+25=31 | | 4x+.6=x | | (3x-5)/(x^2-1) | | -20=5b | | 6/p=4.437/4.336 | | p+48=66 | | 3x-.8=x | | 113-3n=113 | | 23/10=n/100 | | =(x+7)(x+2) | | log(27)^x=1/3 | | -4(t-17)=-8 | | 301/200=n/100 | | y^2+y=4 | | 8q^2-5q-7q^2+9q-32=0 | | -3(7-3m)+5m=19m-11 | | 6/3/2=12/n | | y(y)+y-4=0 | | 17/400=n/100 | | m-21.72=-4.71 | | .75m=12.75 | | 2(s+-7)=-20 | | .75m=12.75m | | 4x-3(x-5)=7x-5(x+5) | | -4x+3y=-3y-4 | | A=qv+x | | m/12=324/18 | | 9.87+m=26.87 | | -45=-0.5(x-7.1) | | 167/100=n/100 |

Equations solver categories